Take the inverse tangent of both sides of the equation to extract <math><mstyle displaystyle="true"><mi>x</mi></mstyle></math> from inside the tangent.

Evaluate <math><mstyle displaystyle="true"><mi>arctan</mi><mrow><mo>(</mo><mfrac><mrow><msqrt><mn>3</mn></msqrt></mrow><mrow><mn>2</mn></mrow></mfrac><mo>)</mo></mrow></mstyle></math> .

The tangent function is positive in the first and third quadrants. To find the second solution, add the reference angle from <math><mstyle displaystyle="true"><mi>π</mi></mstyle></math> to find the solution in the fourth quadrant.

Remove parentheses.

Remove parentheses.

Add <math><mstyle displaystyle="true"><mn>3.14159265</mn></mstyle></math> and <math><mstyle displaystyle="true"><mn>0.71372437</mn></mstyle></math> .

The period of the function can be calculated using <math><mstyle displaystyle="true"><mfrac><mrow><mi>π</mi></mrow><mrow><mrow><mo>|</mo><mi>b</mi><mo>|</mo></mrow></mrow></mfrac></mstyle></math> .

Replace <math><mstyle displaystyle="true"><mi>b</mi></mstyle></math> with <math><mstyle displaystyle="true"><mn>1</mn></mstyle></math> in the formula for period.

The absolute value is the distance between a number and zero. The distance between <math><mstyle displaystyle="true"><mn>0</mn></mstyle></math> and <math><mstyle displaystyle="true"><mn>1</mn></mstyle></math> is <math><mstyle displaystyle="true"><mn>1</mn></mstyle></math> .

Divide <math><mstyle displaystyle="true"><mi>π</mi></mstyle></math> by <math><mstyle displaystyle="true"><mn>1</mn></mstyle></math> .

The period of the <math><mstyle displaystyle="true"><mi>tan</mi><mrow><mo>(</mo><mi>x</mi><mo>)</mo></mrow></mstyle></math> function is <math><mstyle displaystyle="true"><mi>π</mi></mstyle></math> so values will repeat every <math><mstyle displaystyle="true"><mi>π</mi></mstyle></math> radians in both directions.

Consolidate the answers.

Do you know how to Solve for x in Radians tan(x)=( square root of 3)/2? If not, you can write to our math experts in our application. The best solution for your task you can find above on this page.

Name | one billion six hundred thirty-three million four hundred two thousand five hundred six |
---|

- 1633402506 has 8 divisors, whose sum is
**3266805024** - The reverse of 1633402506 is
**6052043361** - Previous prime number is
**3**

- Is Prime? no
- Number parity even
- Number length 10
- Sum of Digits 30
- Digital Root 3

Name | one billion eight hundred eighty-two million seven hundred fifty-two thousand nine hundred eighty-five |
---|

- 1882752985 has 4 divisors, whose sum is
**2259303588** - The reverse of 1882752985 is
**5892572881** - Previous prime number is
**5**

- Is Prime? no
- Number parity odd
- Number length 10
- Sum of Digits 55
- Digital Root 1

Name | one billion three hundred forty million two hundred fifty-six thousand five hundred twelve |
---|

- 1340256512 has 2048 divisors, whose sum is
**40094113536** - The reverse of 1340256512 is
**2156520431** - Previous prime number is
**47**

- Is Prime? no
- Number parity even
- Number length 10
- Sum of Digits 29
- Digital Root 2